This code calculates the **sum of all numbers** in the...

August 22, 2025 at 11:34 AM

const sum = numbers.reduce((acc, val) => acc + val, 0);

This code calculates the sum of all numbers in the array numbers. Here's how it works:

  1. numbers.reduce(callback, initialValue):

    • The reduce method iterates through the elements of the numbers array and accumulates a single result.
    • It takes a callback function (here (acc, val) => acc + val) and an optional initialValue, which is 0 in this case.
  2. Callback function:

    • The callback (acc, val) => acc + val:
      • acc is the accumulator that holds the running total.
      • val is the current element of the array being processed.
      • acc + val adds the current array element to the accumulator.
  3. Initial Value:

    • The accumulator acc starts at 0, as specified by the second argument to reduce.
  4. Process:

    • The reduce method iterates through all elements of numbers, adding each value to acc, and returns the final sum.

Example Usage:

If numbers = [1, 2, 3, 4], the result of this code will be:

  • Initial value of acc = 0.
  • First iteration: acc = 0 + 1 = 1.
  • Second iteration: acc = 1 + 2 = 3.
  • Third iteration: acc = 3 + 3 = 6.
  • Fourth iteration: acc = 6 + 4 = 10.
  • Result: sum = 10.

In summary, this code computes and returns the total sum of the elements in the numbers array.

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