This code calculates the **sum of all numbers** in the...
August 22, 2025 at 11:34 AM
This code calculates the sum of all numbers in the array numbers
. Here's how it works:
-
numbers.reduce(callback, initialValue)
:- The
reduce
method iterates through the elements of thenumbers
array and accumulates a single result. - It takes a callback function (here
(acc, val) => acc + val
) and an optionalinitialValue
, which is0
in this case.
- The
-
Callback function:
- The callback
(acc, val) => acc + val
:acc
is the accumulator that holds the running total.val
is the current element of the array being processed.acc + val
adds the current array element to the accumulator.
- The callback
-
Initial Value:
- The accumulator
acc
starts at0
, as specified by the second argument toreduce
.
- The accumulator
-
Process:
- The
reduce
method iterates through all elements ofnumbers
, adding each value toacc
, and returns the final sum.
- The
Example Usage:
If numbers = [1, 2, 3, 4]
, the result of this code will be:
- Initial value of
acc = 0
. - First iteration:
acc = 0 + 1 = 1
. - Second iteration:
acc = 1 + 2 = 3
. - Third iteration:
acc = 3 + 3 = 6
. - Fourth iteration:
acc = 6 + 4 = 10
. - Result:
sum = 10
.
In summary, this code computes and returns the total sum of the elements in the numbers
array.
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