The provided function `int intLength(int x)` calculates and returns the...
August 31, 2025 at 03:35 AM
The provided function int intLength(int x)
calculates and returns the number of digits in the integer x
. Here's a breakdown of what the code does:
-
Edge case for
x == 0
:- If
x
is0
, the function immediately returns1
, because the number0
has exactly one digit.
- If
-
Handle negative numbers:
- The
std::abs(x)
function is used to take the absolute value ofx
, ensuring that the function works correctly for both positive and negative numbers.
- The
-
Initialize variables:
y
is assigned the absolute value ofx
.size
is initialized to0
, and it will be used to count the number of digits.
-
Loop:
- A
while
loop iterates as long asy >= 1
. In each iteration:size
is incremented by1
, representing an additional digit of the integer.y
is divided by10
(using integer division) to "remove" the last digit by shifting all digits to the right.
- A
-
Return result:
- Once
y
becomes less than1
(i.e., all digits have been processed), the function exits the loop and returns thesize
, which represents the total number of digits in the integerx
.
- Once
Examples:
intLength(0)
→ Returns1
(since 0 has one digit).intLength(123)
→ Returns3
(123 has three digits).intLength(-4567)
→ Returns4
(the absolute value 4567 has four digits).intLength(10000)
→ Returns5
(10000 has five digits).
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