The provided function `int intLength(int x)` calculates and returns the...

August 31, 2025 at 03:35 AM

Int intLength(int x){ if(x == 0){return 1;} int y = std::abs(x), size = 0; while(y >= 1){ size++; y /= 10; } return size; }

The provided function int intLength(int x) calculates and returns the number of digits in the integer x. Here's a breakdown of what the code does:

  1. Edge case for x == 0:

    • If x is 0, the function immediately returns 1, because the number 0 has exactly one digit.
  2. Handle negative numbers:

    • The std::abs(x) function is used to take the absolute value of x, ensuring that the function works correctly for both positive and negative numbers.
  3. Initialize variables:

    • y is assigned the absolute value of x.
    • size is initialized to 0, and it will be used to count the number of digits.
  4. Loop:

    • A while loop iterates as long as y >= 1. In each iteration:
      • size is incremented by 1, representing an additional digit of the integer.
      • y is divided by 10 (using integer division) to "remove" the last digit by shifting all digits to the right.
  5. Return result:

    • Once y becomes less than 1 (i.e., all digits have been processed), the function exits the loop and returns the size, which represents the total number of digits in the integer x.

Examples:

  1. intLength(0) → Returns 1 (since 0 has one digit).
  2. intLength(123) → Returns 3 (123 has three digits).
  3. intLength(-4567) → Returns 4 (the absolute value 4567 has four digits).
  4. intLength(10000) → Returns 5 (10000 has five digits).
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