The provided code defines a method `Writeln` for a struct...
August 30, 2025 at 11:19 PM
The provided code defines a method Writeln
for a struct type MasterTerminal
. Let's break it down:
Code Analysis:
func (w *MasterTerminal) Writeln(msg string) {
fmt.Fprintf(w.conn, "%s", msg)
}
-
Method Definition:
(w *MasterTerminal)
indicates thatWriteln
is a method with a pointer receiver for theMasterTerminal
struct. This means the method operates on the instance (or object) ofMasterTerminal
.
-
The
msg
Parameter:- This method takes a single argument,
msg
, which is astring
. This string likely represents the message to be written.
- This method takes a single argument,
-
fmt.Fprintf
:fmt.Fprintf
is a function used to format and write data to anio.Writer
. In this case,w.conn
is being written to.%s
is a format specifier to write the stringmsg
exactly as it is.w.conn
must implement theio.Writer
interface (e.g., it could be a network connection, a file, or a buffer).
-
Meaning:
- The
Writeln
method writes themsg
string tow.conn
using theFprintf
function. However, this does not append a newline character (\n
) to the message, despite the name "Writeln" (which might confuse readers expecting a newline).
- The
Assumptions Based on Usage:
w.conn
could be any object supporting theio.Writer
interface, such as a network socket or standard output.- The string variable
test
defined as:
test = `
art here
here and here
`
... is a multiline string and might be passed to the Writeln
method as the msg
argument. Executing w.Writeln(test)
would write this entire multiline string, unchanged, to w.conn
.
Summary:
The Writeln
method writes the provided string msg
to w.conn
exactly as it is. However, despite its name, it does not automatically append a newline at the end of the message.
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