This code snippet uses the `pandas` and `datetime` libraries in...

June 30, 2025 at 12:26 PM

YEAR_END_THEN = pd.to_datetime('today') YEAR_START_NOW = YEAR_END_THEN - timedelta(days=8*365)

This code snippet uses the pandas and datetime libraries in Python to calculate a date that is approximately 8 years before today. Here's a step-by-step explanation:

  1. pd.to_datetime('today'):

    • This converts the current date and time (i.e., today's date) into a Pandas Timestamp object. The variable YEAR_END_THEN will hold a Pandas Timestamp object corresponding to the current date and time.
  2. timedelta(days=8*365):

    • The timedelta object is used to represent a duration of time, specifically 8 years here. This is calculated by assuming each year has 365 days (ignoring leap years). It results in a timedelta object equivalent to 8 years expressed in days.
  3. YEAR_END_THEN - timedelta(days=8*365):

    • This subtracts the timedelta (8 years or 2920 days) from the current date held in YEAR_END_THEN. The subtraction results in a new date that is approximately 8 years before the current date.
  4. YEAR_START_NOW:

    • This variable is assigned the computed date, which is 8 years before today.

Summary:

The code calculates the date that is approximately 8 years prior to today's date and stores it in the variable YEAR_START_NOW.

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