Let's break down the code and understand its behavior step...

Let's break down the code and understand its behavior step by step:

print(None, print(1, 2))

Inner print function:

• Python evaluates expressions from inside out, so print(1, 2) will be executed first.
• print(1, 2) prints 1 2 to the console and returns None, as the print() function in Python always returns None.

Thus, after executing the inner print(1, 2), it will:

1. Print 1 2 to the console.
2. Leave None as its return value.

Outer print function:

• After evaluating print(1, 2), the None returned by it will be used in the outer print function call.
• So the outer print() becomes effectively: print(None, None) because None is explicitly provided as the first argument, and the result of print(1, 2) is the second argument.

The outer print(None, None) will:

1. Print None None to the console.

Final Output:

1. The first line printed is 1 2 (from print(1, 2)).
2. The second line printed is None None (from the outer print).

Summary:

This code:

1. Prints 1 2 on the first line.
2. Prints None None on the second line.