Here is what each function in your code does: 1. **`bool...
August 31, 2025 at 03:26 AM
Here is what each function in your code does:
-
bool isPowerOfTwo(long n)
:- This function determines if the integer
n
is a power of two. - It works by checking two conditions:
n > 0
: Ensures the number is positive.(n & (n - 1)) == 0
: Uses bitwise AND to verify thatn
has only a single bit set (a property of powers of two).
- Example:
isPowerOfTwo(4)
→true
(4 is (2^2)).isPowerOfTwo(6)
→false
.
- This function determines if the integer
-
long lowerPowerOfTwo(const long &n)
:- This function finds the largest power of two less than or equal to the input
n
. - It iteratively doubles
currentPower
(starting at 1) until it exceedsn
, then returns the previous value (currentPower / 2
). - Example:
lowerPowerOfTwo(15)
→8
(largest power of two ≤ 15).lowerPowerOfTwo(20)
→16
.
- This function finds the largest power of two less than or equal to the input
-
int findMedian(std::vector<int> numbers)
:- This function calculates the median of a vector of integers.
- Steps:
- Sorts the vector in ascending order.
- Finds the median using the size of the vector:
- If the size is odd, returns the middle element.
- If the size is even, returns the average of the two middle elements.
- Example:
findMedian({1, 3, 2})
→2
(sorted: {1, 2, 3}, median is 2).findMedian({4, 2, 1, 3})
→2.5
(sorted: {1, 2, 3, 4}, median is (2 + 3) / 2).
-
int intSize(int x)
:- This function calculates the number of digits in a positive integer
x
. - It does so by repeatedly dividing
x
by 10 and incrementingsize
untilx
becomes less than 1. - Example:
intSize(1)
→1
(1 has 1 digit).intSize(1234)
→4
(1234 has 4 digits).- Note: Negative numbers are not explicitly handled, so for negatives, the behavior may not be as intended.
- This function calculates the number of digits in a positive integer
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