The code performs the following steps: ### Code Breakdown: 1. **Line 1:**...

January 2, 2025 at 09:02 AM

a = [1,2,3] b = [2,3,4]Python binary search algorithm c = set(a) & set(b)

The code performs the following steps:

Code Breakdown:

  1. Line 1: a = [1, 2, 3]
    This creates a list a containing the elements [1, 2, 3].

  2. Line 2: b = [2, 3, 4]
    This creates a list b containing the elements [2, 3, 4].

  3. Line 3: c = set(a) & set(b)

    • set(a) converts the list a into a set {1, 2, 3}.
    • set(b) converts the list b into a set {2, 3, 4}.
    • The & operator is the set intersection operator in Python. It finds the common elements between the two sets set(a) and set(b).

Outcome:

The intersection of {1, 2, 3} and {2, 3, 4} is {2, 3}. So, the variable c will have the set {2, 3}.

Final Answer:

The code computes the intersection of two lists (a and b) by converting them into sets and finding their common elements. The result is stored in the variable c as a set containing the elements {2, 3}.

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