The code initializes a variable `i` with a value of...

March 28, 2023 at 03:34 PM

i = 0 i++ print(i) print(i++)

The code initializes a variable i with a value of 0. Then, the i++ statement increments the value of i by 1. The first print statement outputs the current value of i, which is 1.

The second print statement also outputs the current value of i, which is still 1. However, the i++ statement after it increments the value of i by 1 again, so the next time i is printed, its value will be 2.

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