The code initializes a variable `i` with a value of...
March 28, 2023 at 03:34 PM
The code initializes a variable i
with a value of 0. Then, the i++
statement increments the value of i
by 1. The first print
statement outputs the current value of i
, which is 1.
The second print
statement also outputs the current value of i
, which is still 1. However, the i++
statement after it increments the value of i
by 1 again, so the next time i
is printed, its value will be 2.
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