The given code performs the following actions: 1. `a = [1,2,3]`:...
January 2, 2025 at 12:53 PM
The given code performs the following actions:
a = [1,2,3]
: This initializes a lista
with the elements[1, 2, 3]
.b = [2,3,4]
: This initializes another listb
with the elements[2, 3, 4]
.c = set(a) & set(b)
:set(a)
converts the lista
into a set, which would be{1, 2, 3}
.set(b)
converts the listb
into a set, which would be{2, 3, 4}
.- The
&
operator is the set intersection operator, which computes the common elements between the two sets. - The result of the intersection operation (
set(a) & set(b)
) would be{2, 3}
, as these are the elements common to botha
andb
.
At the end, the variable c
will hold the value {2, 3}
which is a set containing the common elements between a
and b
.
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