This code performs the following tasks: 1. **Includes the Standard Input/Output...

This code performs the following tasks:

1. Includes the Standard Input/Output library: The #include <stdio.h> directive is included to use input and output functions, such as scanf and printf.

2. Defines the maxmin function:

   • The maxmin function takes three integers (prob1, prob2, prob3) as well as two pointers (*max and *min).
   • It calculates the maximum and minimum values among the three integers and stores the results in the memory locations pointed to by the *max and *min pointers, respectively.
   • The implementation iterates through the input integers prob1, prob2, and prob3, and updates the maximum (*max) and minimum (*min) values accordingly.

3. Calculates the maximum and minimum values provided by the user:

   • In the main function:
     • It declares variables x, y, and z to read three integers entered by the user via scanf.
     • If the input isn't exactly three integers, it prints "n/a" and terminates the program with a return code 0.
     • If input is valid, it declares variables max and min to store the calculated maximum and minimum values.
     • It calls the maxmin function, passing the user inputs x, y, and z, as well as the addresses (&max, &min) where the max and min values should be stored.
     • Finally, it prints the maximum and minimum values.

4. Outputs the calculation results:

   • After the maxmin function is executed, the program outputs the calculated maximum and minimum values separated by a space.

Example Execution:

Input:

5 10 3

Execution Process:

• x = 5, y = 10, z = 3
• maxmin(5, 10, 3, &max, &min) gets invoked.
• Inside maxmin:
  • *max and *min are initialized to prob1 (5).
  • prob2 (10) updates *max to 10 since it's greater than the current value of *max (5).
  • prob2 (10) does not update *min because it's greater than the current value of *min (5).
  • prob3 (3) does not update *max because it's less than the current value of *max (10).
  • prob3 (3) updates *min to 3 because it's less than the current value of *min (5).
• max = 10, min = 3.
• The program prints 10 3.

Output:

10 3

This code is functional, and the maxmin function logically handles determining the maximum and minimum values. There are no errors or bugs in the implementation.