The given code performs the following actions: 1. `a = [1,...

December 30, 2024 at 11:39 AM

a = [1,2,3] b = [2,3,4]Java code to calculate the area of a circle c = set(a) & set(b)

The given code performs the following actions:

  1. a = [1, 2, 3]: A list a is created with the elements 1, 2, and 3.
  2. b = [2, 3, 4]: A list b is created with the elements 2, 3, and 4.
  3. c = set(a) & set(b): Both lists a and b are converted into sets. The & (ampersand) operator is then used to find the intersection of the two sets. The intersection retrieves only the elements that are common between a and b.

Result:

  • set(a) becomes {1, 2, 3}.
  • set(b) becomes {2, 3, 4}.
  • The intersection of {1, 2, 3} and {2, 3, 4} is {2, 3}.

Finally, c will be assigned the value {2, 3}, which is a set containing the common elements between a and b.

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