This code calculates the average of scores but does so...
September 2, 2025 at 03:46 AM
This code calculates the average of scores but does so in an incorrect way due to type mismatch. Here's a breakdown of what the code does:
-
double total = 25.5;
- Declares a variable
total
of typedouble
and initializes it with the value25.5
.
- Declares a variable
-
int numScores = 3;
- Declares an integer variable
numScores
and initializes it with the value3
.
- Declares an integer variable
-
int ave = total / numScores;
- This statement attempts to divide the
double
valuetotal
(25.5) by the integernumScores
(3) and assigns the result to the integer variableave
. - Since
ave
is anint
, the fractional part of the result is truncated (not rounded). The actual calculation25.5 / 3
equals8.5
, but sinceave
is an integer, it will store only8
.
- This statement attempts to divide the
Summary
This code calculates the average as an integer, truncating any fractional part. It is not the correct way to calculate a precise average if you aim to retain decimal precision. To fix it, you could either declare ave
as a double
type or explicitly cast total
to int
if the truncation is intentional.
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