This code calculates the average of scores but does so...

September 2, 2025 at 03:46 AM

double total = 25.5; int numScores = 3; int ave = total/numScores;

This code calculates the average of scores but does so in an incorrect way due to type mismatch. Here's a breakdown of what the code does:

  1. double total = 25.5;

    • Declares a variable total of type double and initializes it with the value 25.5.
  2. int numScores = 3;

    • Declares an integer variable numScores and initializes it with the value 3.
  3. int ave = total / numScores;

    • This statement attempts to divide the double value total (25.5) by the integer numScores (3) and assigns the result to the integer variable ave.
    • Since ave is an int, the fractional part of the result is truncated (not rounded). The actual calculation 25.5 / 3 equals 8.5, but since ave is an integer, it will store only 8.

Summary

This code calculates the average as an integer, truncating any fractional part. It is not the correct way to calculate a precise average if you aim to retain decimal precision. To fix it, you could either declare ave as a double type or explicitly cast total to int if the truncation is intentional.

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