This MATLAB code calculates and displays the point of intersection...
August 28, 2025 at 07:08 PM
This MATLAB code calculates and displays the point of intersection of two lines defined by their slopes (m_1, m_2) and y-intercepts (b_1, b_2). Here's what each section does:
-
Random Initialization of Line Parameters:
- Slopes ((m_1) and (m_2)) and y-intercepts ((b_1) and (b_2)) for the two lines are initialized using the
rand
function to generate random numbers between -5 and 5.
- Slopes ((m_1) and (m_2)) and y-intercepts ((b_1) and (b_2)) for the two lines are initialized using the
-
Static Testing of Specific Line Values:
- There is a commented-out block with specific values for (m_1), (b_1), (m_2), and (b_2). If uncommented, these values are used instead of the randomized ones, allowing the user to test specific cases (e.g., (m_1 = 1, b_1 = 0, m_2 = 0, b_2 = 3)).
-
Display Line Parameters:
- The
fprintf
function prints the values of (m_1), (b_1), (m_2), and (b_2) to two decimal places.
- The
-
Solve for Intersection:
- The code computes the (x)-coordinate of the intersection of the two lines using the formula: [ x = \frac{b_2 - b_1}{m_1 - m_2} ] This is derived from equating the equations of the two lines: [ y = m_1x + b_1 \quad \text{and} \quad y = m_2x + b_2 ]
-
Substitute (x) to Compute (y):
- The computed (x)-value is substituted into the equation of the first line ((y = m_1x + b_1)) to find the (y)-coordinate of the intersection.
-
(Bug Note):
- There is a mistake in this code: the calculation of
x
uses(m1-b2)
in the denominator instead of(m1-m2)
. This will lead to incorrect results unless fixed.
- There is a mistake in this code: the calculation of
-
Point of Intersection Display:
- The output shows the (x)- and (y)-coordinates of the intersection point.
In summary, this code duplicates the interaction for two lines, computes their intersection point, and displays its coordinates, but contains an error in the x
calculation that should be fixed to work correctly.
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