This code generates and prints a diamond pattern made up...
This code generates and prints a diamond pattern made up of asterisks (*
). The diamond is symmetric and consists of an upper triangular part (including the middle row) and a lower triangular part (excluding the middle row).
Here's the breakdown of what it does:
-
Initialize the size of the diamond:
-
The variable
n
determines the number of rows in the upper half of the diamond (or the distance from the middle row to the top of the diamond). -
For the given value
n = 4
, the diamond will consist of2 * n - 1 = 7
rows.
-
-
Upper half (including middle row):
-
The outer loop (
for (int i = 1; i <= n; i++)
) iterates fromi = 1
toi = n
. This loop builds the rows for the top part of the diamond. -
Spaces: The first inner loop (
for (int j = 1; j <= n - i; j++)
) prints spaces before the stars to center-align the stars in the diamond shape. -
Stars: The second inner loop (
for (int k = 1; k <= 2 * i - 1; k++)
) handles the printing of stars. The number of stars in each row follows the formula2 * i - 1
. -
After printing the spaces and stars for a row, a newline is added with
System.out.println()
.
-
-
Lower half (excluding middle row):
-
The outer loop for the lower half (
for (int i = n - 1; i >= 1; i--)
) iterates downward fromn - 1
to1
. This loop generates rows for the bottom part of the diamond. -
The logic for printing spaces and stars is the same as in the upper half, except that the number of stars decreases as
i
decreases.
-
-
Example Output: For
n = 4
, the output looks like this:* *** ***** ******* ***** *** *
- The diamond has 7 rows, with the middle row (
n = 4
) being the widest at 7 stars (2 * 4 - 1
). The number of stars decreases symmetrically in the lower half.
- The diamond has 7 rows, with the middle row (