The code has the following behavior related to variable scope: 1....

The code has the following behavior related to variable scope:

1. The variable myName is defined outside the function, making it a global variable.

   • Therefore, it is accessible both inside and outside the function.

2. The variable yourName is defined inside the say_your_name function, making it a local variable. Local variables are accessible only within the function in which they are defined.

Now, let's analyze each line:

• Line 5: print(yourName)
  This will work because yourName is a local variable defined within the say_your_name function, and print(yourName) is executed inside the same scope where yourName exists.

• Line 8: print(myName)
  This will also work because myName is a global variable, and global variables are accessible inside functions.

• Line 9: print(yourName)
  This will not work because yourName is a local variable that exists only within the say_your_name function. When we try to access it outside the function on line 9, it will result in a NameError.

Final Answer:

Line 9 will not work due to scope issues.