This code performs the following actions: 1. **Initialization**: A variable `myVar`...

September 15, 2025 at 02:03 AM

int myVar = 1; for(int i = 1; i <= 100; i++){ myVar = myVar << 1; if(myVar != i * 2){ return false; } } // bitwise left is equal to doubling the current value! return true;

This code performs the following actions:

  1. Initialization: A variable myVar is set to 1.

    int myVar = 1;
    
  2. For Loop: A for loop runs i from 1 to 100 (inclusive).

    for (int i = 1; i <= 100; i++) {
    ...
    }
    
  3. Bitwise Left Shift: Within the loop, the line:

    myVar = myVar << 1;
    

    performs a bitwise left shift operation on myVar. This operation doubles the value of myVar because shifting the bits to the left by 1 is equivalent to multiplying by 2.

  4. Comparison: Inside the loop, the code checks if the new value of myVar is not equal to i * 2.

    if (myVar != i * 2) {
        return false;
    }
    

    If the condition is true (myVar is not equal to i * 2), the code immediately returns false.

  5. Return Statement: If the loop completes without triggering the if condition (i.e., it finds no mismatches), the code exits the loop and returns true.

    return true;
    

What does the code do?

  • It checks if, for each iteration, myVar (doubled using bitwise left shift) is always equal to i * 2. Since 1 << 1 starts doubling from 2, and so on, the values of myVar will indeed match i * 2.

  • The code ultimately confirms that repeated left-shifting produces the same result as multiplying i by 2.

Result:

  • The function will always return true, as myVar << 1 (left shift) and i * 2 will align for every iteration of the loop.
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