The provided code attempts to perform the following tasks but...

June 29, 2025 at 10:13 PM

YEAR_END_THEN = datetime.today().strftime('%Y-%m-%d') YEAR_START_NOW = YEAR_END_THEN - timedelta(days=8*365)

The provided code attempts to perform the following tasks but will actually throw an error. Let me break this down:

  1. YEAR_END_THEN = datetime.today().strftime('%Y-%m-%d'):

    • This line uses Python's datetime module to get the current date (datetime.today()), and formats it as a string in the format YYYY-MM-DD (e.g., "2023-10-29" if today is October 29, 2023). This assigns a string value to the variable YEAR_END_THEN.
  2. YEAR_START_NOW = YEAR_END_THEN - timedelta(days=8*365):

    • This line attempts to calculate a date 8 years before YEAR_END_THEN. However, YEAR_END_THEN is a string, not a datetime object. Thus, subtracting timedelta (a time duration object) from a string will result in a TypeError.
    • To make this work, YEAR_END_THEN would need to be converted back to a datetime object using datetime.strptime.

Corrected Version (to achieve the desired functionality):

from datetime import datetime, timedelta

YEAR_END_THEN = datetime.today()  # Current datetime
YEAR_START_NOW = YEAR_END_THEN - timedelta(days=8*365)  # Subtract 8 years' worth of days

In this corrected version:

  • YEAR_END_THEN is a datetime object representing the current moment.
  • YEAR_START_NOW is a datetime object representing a date approximately 8 years earlier.
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