This Go code demonstrates how slices in Go can be...
September 15, 2025 at 07:04 AM
This Go code demonstrates how slices in Go can be manipulated by altering their length and capacity using slicing operations. Here's a breakdown of what it does:
1. Initial Setup
s := []int{2, 3, 5, 7, 11, 13}
printSlice(s)
- A slice
s
is initialized with six integers:[2, 3, 5, 7, 11, 13]
. printSlice(s)
is called, which prints the length, capacity, and elements of the slice:len=6 cap=6 [2 3 5 7 11 13]
2. Slice the slice to zero length
s = s[:0]
printSlice(s)
- The slice
s
is updated to have a length of0
usings[:0]
. This operation sets the slice length to zero while keeping the capacity unchanged. printSlice(s)
prints:len=0 cap=6 []
3. Extend the slice length
s = s[:4]
printSlice(s)
- The slice
s
is extended back to length4
usings[:4]
. This restores the first four elements of the original slice because the capacity is still6
, allowing the slice to "grow back" up to this limit. printSlice(s)
prints:len=4 cap=6 [2 3 5 7]
4. Drop the first two values
s = s[2:]
printSlice(s)
- The slice
s
is updated to drop the first two elements usings[2:]
. This operation moves the slice's starting position two steps forward, reducing both its length and capacity relative to the original slice. printSlice(s)
prints:len=2 cap=4 [5 7]
5. The printSlice Function
func printSlice(s []int) {
fmt.Printf("len=%d cap=%d %v\n", len(s), cap(s), s)
}
- This helper function uses
fmt.Printf
to print the current length, capacity, and elements of a given slice.
Summary of Outputs
When you run the program, the output will be:
len=6 cap=6 [2 3 5 7 11 13]
len=0 cap=6 []
len=4 cap=6 [2 3 5 7]
len=2 cap=4 [5 7]
This code illustrates how Go slices are dynamic and can be resized and manipulated while sharing their underlying array.
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