This code defines a `MyClass` that searches for two distinct...

July 4, 2025 at 06:56 PM

class MyClass: def __init__(self, vals): self.lookup = {} self.vals = vals def method(self, target): for i in range(len(self.vals)): num = self.vals[i] if target - num in self.lookup: return (self.lookup[target - num], i) self.lookup[num] = i a = MyClass([10,20,10,40]) res1 = a.method(50)[0] res2 = a.method(30)[1] b = MyClass([10,20,10,40]) res3 = b.method(30)[1]

This code defines a MyClass that searches for two distinct indices in a list whose corresponding values sum to a target value. Let's break it down step by step:

Code Walkthrough

  1. __init__ method:

    • The constructor __init__ initializes two attributes:
      • self.lookup: An empty dictionary intended to store previously visited vals values as keys and their indices as values.
      • self.vals: A list of numbers provided when creating a MyClass instance.
  2. method function:

    • Accepts a target value.
    • Iterates through each value in the vals list.
    • For each value in vals, it:
      1. Computes the difference between the target and the current number num (target - num).
      2. Checks if this difference exists in the self.lookup dictionary:
        • If it exists, the method returns a tuple: (index of target - num, index of num).
      3. If the difference does not exist, it adds the current value num with its index i to the self.lookup dictionary for potential future matches.
  3. Usage:

    • The code creates two instances of MyClass and performs specific operations:
      • First Instance:

        1. The a object is initialized with [10, 20, 10, 40].
        2. The method a.method(50) finds indices (1, 3) because vals[1] + vals[3] = 20 + 40 = 50. The first index (1) is stored in res1.
        3. The method a.method(30) finds indices (0, 1) because vals[0] + vals[1] = 10 + 20 = 30. The second index (1) is stored in res2.
      • Second Instance:

        1. The b object is initialized with [10, 20, 10, 40].
        2. The method b.method(30) called on b again finds indices (0, 1) for vals[0] + vals[1] = 10 + 20 = 30. The second index (1) is stored in res3.

Outputs:

  • res1: This is the first index from the tuple returned by a.method(50), which is 1.
  • res2: This is the second index from the tuple returned by a.method(30), which is 1.
  • res3: This is the second index from the tuple returned by b.method(30), which is 1.

Key Observations:

  • Instance-specific state: Each object of MyClass has its own independent lookup dictionary. This is why results of a and b don't interfere with one another.
  • Purpose: The method function essentially solves a variation of the "two-sum problem", where it finds two indices such that their values add up to a given target.
Generate your own explanations
Download our vscode extension
Read other generated explanations

Built by @thebuilderjr
Sponsored by beam analytics
Read our terms and privacy policy
Forked from openai-quickstart-node