The provided code attempts to append `row_obj_list` to the `"rows"`...
The provided code attempts to append row_obj_list
to the "rows"
key of a nested dictionary structure. Specifically, this dictionary structure is within res_page["week_data"][page_table_idx]
.
Here's the breakdown of what the code does and why you're receiving a KeyError
:
Code Breakdown:
res_page
: Presumably this is a dictionary containing the key"week_data"
.res_page["week_data"]
: Accesses the value associated with the"week_data"
key; the value is likely a dictionary or list.res_page["week_data"][page_table_idx]
: Accesses the element indexed bypage_table_idx
within"week_data"
. If"week_data"
is a dictionary,page_table_idx
is expected to be a valid key. If it is a list,page_table_idx
must be an integer index.res_page["week_data"][page_table_idx]["rows"]
: This looks for a key named"rows"
in the dictionary at the locationres_page["week_data"][page_table_idx]
.- Error (
KeyError: 'rows'
): The error means that the"rows"
key does not exist, and the code cannot proceed to theappend
operation.
What the Code Tries to Do:
The code is attempting to:
- Access the
"rows"
key within the nested dictionary atres_page["week_data"][page_table_idx]
. - Append
row_obj_list
(likely a list or similar object) to the value associated with the"rows"
key.
However, since the "rows"
key does not exist in that nested dictionary, Python raises a KeyError
.
Why the Error Occurs:
The "rows"
key is missing in res_page["week_data"][page_table_idx]
. Before you can append to a list associated with a key, the key itself must exist and reference a list.
How to Fix the Code:
To fix the error, you can ensure the "rows"
key exists and is initialized to a list before attempting to append. For instance:
# Ensure that the "rows" key exists and is a list
if "rows" not in res_page["week_data"][page_table_idx]:
res_page["week_data"][page_table_idx]["rows"] = []
# Now safely append
res_page["week_data"][page_table_idx]["rows"].append(row_obj_list)
This code checks if "rows"
is present; if not, it initializes it as an empty list, allowing the subsequent append
to succeed without error.