This code checks if the first word of the string...

August 25, 2025 at 05:01 PM

street_types = {'ST', 'STREET', 'AVE', 'AVENUE', 'RD', 'ROAD', 'DR', 'DRIVE', 'BLVD', 'BOULEVARD', 'LN', 'LANE', 'CT', 'COURT', 'WAY', 'HWY', 'HIGHWAY', 'PKWY', 'PARKWAY', 'PL', 'PLACE', 'TER', 'TERRACE', 'CIR', 'CIRCLE', 'TRL', 'TRAIL', 'ALY', 'ALLEY', 'ROW', 'SQ', 'SQUARE'} line = Drive San Jose if line.split()[0].upper() not in street_types: test = True

This code checks if the first word of the string line, when converted to uppercase, is not contained in the set of predefined street types (street_types). It then sets the variable test to True if that condition is met.

Detailed Breakdown:

  1. street_types: A set containing possible abbreviations and full names of street types (e.g., 'ST', 'STREET', 'AVE', 'AVENUE', etc.).

  2. line = Drive San Jose: A string variable line is assigned the value 'Drive San Jose'.

  3. Processing in the if statement:

    • line.split() splits the string line into a list of words, so line.split() results in ['Drive', 'San', 'Jose'].
    • line.split()[0] extracts the first word, which is 'Drive'.
    • .upper() converts 'Drive' to 'DRIVE'.
    • if line.split()[0].upper() not in street_types: Checks whether 'DRIVE' is not in the street_types set.
  4. Outcome:

    • If 'DRIVE' is not in the street_types set, the variable test is set to True.
    • Otherwise, no action is performed because there is no else clause.

In This Case:

  • The first word in line is 'Drive'.
  • 'DRIVE' converted to uppercase is checked against the street_types set.
  • Since 'DRIVE' is in the set, the condition fails, and the variable test would not get assigned in this example.

Summary:

This code is a basic check to validate whether the first word of a given string line is a recognized street type, as defined in the street_types set. If it is not recognized, it sets test to True.

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