This code defines a method called `countSomething` that performs a...

February 4, 2025 at 05:02 AM

public int countSomething (TreeNode root) { if (root == null) return 0; else if (root.getLeft () == null) return countSomething (root.getRight ()) : else if (root.getRight() == null) return countSomething (root.getLeft ()); else return countSomething(root.getRight()) + countSomething(root.getLeft ()) + 1; }

This code defines a method called countSomething that performs a recursive operation on a binary tree. The method appears to count the number of internal nodes (non-leaf nodes) in a binary tree. Here's what the code does, step by step:

  1. Base Case (Empty Tree):

    • If the root is null, the method returns 0, which serves as the base case for the recursion.
  2. Case for a Single Child on the Left (Right Subtree Traversal):

    • If the root's left child (root.getLeft()) is null, the method recursively calls countSomething on the right subtree (root.getRight()).
  3. Case for a Single Child on the Right (Left Subtree Traversal):

    • If the root's right child (root.getRight()) is null, the method recursively calls countSomething on the left subtree (root.getLeft()).
  4. Case for Two Children (Both Subtrees):

    • If the root has both left and right children, the method:
      • Recursively calls countSomething on both the left and right subtrees.
      • Adds 1 to the result (to count the current node as an internal node).

Summary of Functionality:

The method counts the internal nodes (nodes with at least one child) in the binary tree rooted at root. It does not count leaf nodes (nodes with no children).

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