This code defines a function `array_sum` that calculates the sum...

September 13, 2025 at 03:08 AM

#include <stdio.h> #include <stdint.h> int32_t array_sum(int32_t *arr,uint32_t n){ int32_t r = 0; for(int i = 0; i < n; i++){ r += arr[i]; } return r; }

This code defines a function array_sum that calculates the sum of the elements in an array of integers. Here’s a breakdown of what it does:

  1. Include Headers:

    • #include <stdio.h>: Includes the standard input/output library (not directly used in this snippet but commonly used for printing/debugging).
    • #include <stdint.h>: Includes fixed-width integer type definitions (int32_t, uint32_t).
  2. Function Definition:

    • int32_t array_sum(int32_t *arr, uint32_t n): Defines a function named array_sum that takes the following parameters:

      • int32_t *arr: A pointer to an integer array of 32-bit signed integers.
      • uint32_t n: An unsigned 32-bit integer specifying the number of elements in the array.
    • The function returns an int32_t (a 32-bit signed integer).

  3. Variable Initialization:

    • int32_t r = 0;: Initializes a variable r to zero. r will store the running total (sum of array elements).
  4. For Loop:

    • for (int i = 0; i < n; i++): A loop that iterates over the array elements.
      • i starts at 0.
      • The loop continues until i is less than n (the number of elements in the array).
      • i increments by 1 at the end of each iteration.
  5. Summation:

    • Inside the loop, r += arr[i]; adds the i-th element of the array (arr[i]) to r.
  6. Return Statement:

    • After the loop, return r; returns the total sum of all array elements.

Summary:

The function array_sum accepts an array of signed 32-bit integers and its size (n), iterates through the array, computes the sum of all its elements, and returns the total.

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