The provided code defines a **function template** named `printVector` that...

The provided code defines a function template named printVector that prints the elements of a std::vector to the standard output, separated by spaces. Here's a breakdown:

1. Template Declaration:

   template <typename T>
   

   • This specifies that the function is a template, meaning it can operate on a std::vector of any type T.

2. Function Signature:

   void printVector(const std::vector<T>& vec)
   

   • The function printVector accepts a constant reference to a std::vector of type T.

   • Using a const reference avoids copying the vector while ensuring that the function does not modify the original std::vector.

3. Range-based For Loop:

   for (const auto& element : vec)
   

   • Iterates through each element in the vec.
   • The auto& ensures the loop works with any type T that the std::vector contains.
   • The const qualifier ensures that no elements in the vector are modified during iteration.

4. Output Each Element:

   std::cout << element << " ";
   

   • Prints each element of the vector, followed by a space.

5. **Ending Output with a Special Character:

   std::cout << " ";
   

   • Prints an extra space at the end of the output to separate the vector's elements from other output.

Note: The code contains a syntax issue; “ “ uses fancy/curved quotation marks instead of standard double quotes ("). This would cause a compilation error. It should be corrected as:

std::cout << " ";

Example:

If the printVector function is called with the following vector:

std::vector<int> numbers = {1, 2, 3, 4};
printVector(numbers);

The output would be:

1 2 3 4  

(The vector elements, each followed by a space, and an additional trailing space).