The provided code calculates the **factorial** of a given integer...
February 4, 2025 at 09:34 AM
The provided code calculates the factorial of a given integer n
recursively. Here's an explanation of what the code does:
-
Base Case (Stopping Condition):
- If
n <= 1
, the function returns1
. This serves as the base case to prevent infinite recursion, signifying that the factorial of0
or1
is1
.
- If
-
Recursive Call:
- If
n > 1
, the function calculatesn * factorial(n - 1)
. This means it multipliesn
by the factorial ofn - 1
. This process will repeat untiln
reaches1
(or0
), at which point the recursion stops and the intermediate results are multiplied back up the recursion chain.
- If
Example Execution:
If n = 4
, the function evaluates as follows:
factorial(4)
=4 * factorial(3)
factorial(3)
=3 * factorial(2)
factorial(2)
=2 * factorial(1)
factorial(1)
returns1
(base case).
So:
factorial(4)
= 4 * 3 * 2 * 1
= 24
.
Output:
This function computes the factorial of n
, which is mathematically defined as:
[
n! = n \times (n-1) \times (n-2) \times \dots \times 1
]
Generate your own explanations
Download our vscode extension
Read other generated explanations
Built by @thebuilderjr
Sponsored by beam analytics
Read our terms and privacy policy
Forked from openai-quickstart-node