This code defines a variable `myName` in the global scope,...

This code defines a variable myName in the global scope, a function say_your_name, and then calls the function followed by attempting to print yourName.

Here's what the code does:

1. myName = "Jill": This is a global variable, accessible anywhere in the script.

2. def say_your_name(): A function is defined. Inside the function:

   • yourName = "Bob" assigns the local variable yourName with the value "Bob".
   • print(yourName) prints the value of the local variable yourName.
   • print(myName) prints the value of the global variable myName, which is "Jill".
   • Finally, the function returns (implicitly returning None since no value is specified).

3. say_your_name(): This calls the say_your_name function, which:

   • Prints "Bob" (value of yourName from the local scope of the function).
   • Prints "Jill" (value of myName from the global scope).

4. print(yourName): This will cause a scope issue because yourName is a local variable defined inside the say_your_name function. Once the function execution is complete, yourName goes out of scope and is no longer accessible, so trying to reference yourName outside the function will result in a NameError.

Conclusion:

The problematic line is:

print(yourName)

This line will fail because yourName is not defined in the global scope, leading to a NameError.